A dynamometer is attached to two blocks of masses 6 kg and 4 kg. Forces of 20 N and 10 N are applied on the blocks as shown in figure. Find the dynamometer readingin the steady state.
A dynamometer is attached to two blocks of masses 6 kg and 4 kg. Forces of 20 N and 10 N are applied on the blocks as shown in figure. Find the dynamometer readingin the steady state.
Answer: I understand that you have two blocks with masses of 6 kg and 4 kg, and there are forces of 20 N and 10 N applied to these blocks. You want to find the dynamometer reading in the steady state.
Assuming there is friction between the blocks and the surface, and the system is in equilibrium (steady state), we can analyze the forces acting on the blocks.
Let’s label the blocks as follows:
- Block with mass 6 kg: Block A
- Block with mass 4 kg: Block B
The forces acting on Block A are:
- Applied force: 20 N to the right
- Friction force (opposite to the direction of motion, to the left)
The forces acting on Block B are:
- Applied force: 10 N to the right
- Friction force (opposite to the direction of motion, to the left)
The dynamometer reading will be the force required to maintain the equilibrium, which means that the net force on both blocks is zero.
For Block A:
Net force on Block A = Applied force on Block A - Friction force on Block A
20 N - Friction force on Block A = 0
Friction force on Block A = 20 N
For Block B:
Net force on Block B = Applied force on Block B - Friction force on Block B
10 N - Friction force on Block B = 0
Friction force on Block B = 10 N
The dynamometer reading is the sum of the friction forces on both blocks since the dynamometer measures the force required to overcome friction:
Dynamometer reading = Friction force on Block A + Friction force on Block B
Dynamometer reading = 20 N + 10 N
Dynamometer reading = 30 N
So, in the steady state, the dynamometer reading would be 30 N. This is the force required to overcome the friction and maintain equilibrium between the applied forces and friction forces on both blocks.