a five digit number n has all digits different and contains digits 1,3,4,5, and 6 only. if n is the smallest possible number such that it is divisible by 11, then what is the tens place digit of n.
a five digit number n has all digits different and contains digits 1,3,4,5, and 6 only. if n is the smallest possible number such that it is divisible by 11, then what is the tens place digit of n.
Answer: For a number to be divisible by 11, the difference between the sum of its odd-placed digits and the sum of its even-placed digits must be a multiple of 11.
In this case, the odd-placed digits are 1, 4, and 6, and the even-placed digits are 3 and 5. The sum of odd-placed digits is 1 + 4 + 6 = 11, and the sum of even-placed digits is 3 + 5 = 8.
The difference between the sum of odd-placed digits and the sum of even-placed digits is 11 - 8 = 3, which is not a multiple of 11.
Since the difference is not a multiple of 11, the given conditions cannot be satisfied. Therefore, there is no smallest possible number that meets the criteria of having all distinct digits 1, 3, 4, 5, and 6 and being divisible by 11.
As a result, the question cannot be answered as posed.