calculate the radius of gyration of the x component of a triangle with base of 360mm and height 180mm if the triangle is located on the x and y axis.
calculate the radius of gyration of the x component of a triangle with base of 360mm and height 180mm if the triangle is located on the x and y axis.
answer: The radius of gyration of a 2D body is given by the formula:
kx = sqrt(Ix / A)
where kx is the radius of gyration of the x component, Ix is the moment of inertia of the x component, and A is the area of the triangle.
The moment of inertia of a triangle with respect to its centroid is given by the formula:
Ix = (b * h^3) / 36
where b is the base of the triangle and h is its height.
The area of the triangle is given by the formula:
A = (b * h) / 2
Substituting these values, we get:
Ix = (360mm * (180mm)^3) / 36
= 58320000 mm^4
A = (360mm * 180mm) / 2
= 32400 mm^2
So,
kx = sqrt(Ix / A)
= sqrt(58320000 mm^4 / 32400 mm^2)
= 480.62 mm
Therefore, the radius of gyration of the x component of the triangle is approximately 480.62 mm.