find a number whose double is 84 more than its half
find a number whose double is 84 more than its half
Answer: Let’s assume the number is “x”.
According to the problem, “its double is 84 more than its half” can be written as:
2x = (1/2)x + 84
Multiplying both sides by 2 to eliminate the fraction, we get:
4x = x + 168
Subtracting x from both sides, we get:
3x = 168
Dividing both sides by 3, we get:
x = 56
Therefore, the number we are looking for is 56.