Find the next three terms in each sequence then write the rule for finding the nth term

find the next three terms in each sequence then write the rule for finding the nth term

Find the Next Three Terms and the Rule for the nth Term

Sequence 1: 2, 4, 6, 8, …

Answer:

Introduce the Concept: In this sequence, each term increases by a constant amount. We identify this pattern to find subsequent terms and create a formula for the nth term.

Step 1: Present the Clues

  • Terms: 2, 4, 6, 8,…
  • Difference between each term: 4 - 2 = 2, 6 - 4 = 2, 8 - 6 = 2.

Step 2: Deduction Process

  • The sequence is arithmetic with a common difference of 2.
  • To find the next term, add the common difference to the last known term:
    • Next term after 8: (8 + 2 = 10)
    • Next term after 10: (10 + 2 = 12)
    • Next term after 12: (12 + 2 = 14)

Step 3: Finalize the Solution

  • Next three terms: 10, 12, 14
  • Rule for the nth term:
    • Formula for an arithmetic sequence: a_n = a_1 + (n-1) \cdot d
    • Here, (a_1 = 2) and (d = 2).
    • Therefore, a_n = 2 + (n-1) \cdot 2 = 2n

Final Answer:

  • Next three terms: 10, 12, 14
  • Rule for the nth term: a_n = 2n

Sequence 2: 1, 4, 9, 16, …

Answer:

Introduce the Concept: This sequence involves perfect squares. We identify the pattern and create a formula for the nth term.

Step 1: Present the Clues

  • Terms: 1, 4, 9, 16,…
  • These numbers are squares of integers: (1 = 1^2), (4 = 2^2), (9 = 3^2), (16 = 4^2).

Step 2: Deduction Process

  • Identify that each term is squared:
    • Next term after 16 is (5^2 = 25)
    • Next term after 25 is (6^2 = 36)
    • Next term after 36 is (7^2 = 49)

Step 3: Finalize the Solution

  • Next three terms: 25, 36, 49
  • Rule for the nth term: Since each term is the square of its position, a_n = n^2

Final Answer:

  • Next three terms: 25, 36, 49
  • Rule for the nth term: a_n = n^2

Sequence 3: 5, 10, 20, 40, …

Answer:

Introduce the Concept: This sequence demonstrates exponential growth. We assess its pattern and derive a rule for the nth term.

Step 1: Present the Clues

  • Terms: 5, 10, 20, 40,…
  • Each term doubles: (10 = 5 \times 2), (20 = 10 \times 2), (40 = 20 \times 2).

Step 2: Deduction Process

  • Next term after 40: (40 \times 2 = 80)
  • Next term after 80: (80 \times 2 = 160)
  • Next term after 160: (160 \times 2 = 320)

Step 3: Finalize the Solution

  • Next three terms: 80, 160, 320
  • Rule for the nth term: In this sequence, the terms increase by powers of 2. Therefore, a_n = 5 \times 2^{n-1}

Final Answer:

  • Next three terms: 80, 160, 320
  • Rule for the nth term: a_n = 5 \times 2^{n-1}

Sequence 4: 7, 14, 21, 28, …

Answer:

Introduce the Concept: This sequence involves a consistent incremental pattern, identifiable as an arithmetic sequence. Our goal is to find the next terms and formulate the nth term rule.

Step 1: Present the Clues

  • Terms: 7, 14, 21, 28,…
  • Constant difference: (14 - 7 = 7), (21 - 14 = 7), (28 - 21 = 7).

Step 2: Deduction Process

  • Calculate next terms:
    • After 28: (28 + 7 = 35)
    • After 35: (35 + 7 = 42)
    • After 42: (42 + 7 = 49)

Step 3: Finalize the Solution

  • Next three terms: 35, 42, 49
  • Rule for the nth term: Apply the arithmetic formula: a_n = a_1 + (n-1) \cdot d
    • Here, (a_1 = 7) and (d = 7).
    • Therefore, a_n = 7 + (n-1) \cdot 7 = 7n

Final Answer:

  • Next three terms: 35, 42, 49
  • Rule for the nth term: a_n = 7n

This process illustrates how identifying and applying patterns enables the prediction and understanding of sequences in mathematics.