if the word chamber is encrypted as 3823268, what is encrypted value of twinkle
If the word “chamber” is encrypted as “3823268,” what is the encrypted value of “twinkle”?
Answer:
Based on a pattern where:
- Consonants use their alphabetical index but drop any tens digit (e.g., 13 → 3).
- Vowels use their alphabetical index + 1, and if the result is two digits, also drop the tens digit (e.g., 9 + 1 = 10 → 0).
We get the encryption for each letter in “chamber” as follows:
- c (3rd letter) → 3
- h (8th letter) → 8
- a (1st letter, vowel → +1 → 2) → 2
- m (13th letter → drop 1 → 3) → 3
- b (2nd letter) → 2
- e (5th letter, vowel → +1 → 6) → 6
- r (18th letter → drop 1 → 8) → 8
Hence, “chamber” → 3823268.
Applying this exact logic to “twinkle”:
Letter | Alphabetical Index | Vowel/Consonant Rule | Encrypted Digit |
---|---|---|---|
t | 20 | Consonant → drop tens digit (2 → 0) | 0 |
w | 23 | Consonant → drop tens digit (2 → 3) | 3 |
i | 9 | Vowel → (9 + 1 = 10) drop tens digit → 0 | 0 |
n | 14 | Consonant → drop tens digit (1 → 4) | 4 |
k | 11 | Consonant → drop tens digit (1 → 1) | 1 |
l | 12 | Consonant → drop tens digit (1 → 2) | 2 |
e | 5 | Vowel → (5 + 1 = 6) | 6 |
Putting those digits together:
twinkle → 0304126