The marked price of a laptop is Rs. 48750. If the shopkeeper gives two successive discount 10% and x% and sell it in Rs. 40365. Find out the value of x?

Mathematics
1

The marked price of a laptop is Rs. 48750. If the shopkeeper gives two successive discount 10% and x% and sell it in Rs. 40365. Find out the value of x?​

2

Step 1:

48750−\frac{10}{100}×48750)

= 48750 -4875

= 43875

Step 2:

43875 - \frac{x}{100} \times 43875 =40365

​

\implies \frac{x}{100} \times 43875= 3510

\implies x = \frac{3510 \times 100}{43875}
​

\implies \bold{x = 8\%}⟹x=8%

Explain

Let’s assume that the first discount of 10% reduces the marked price by 10/100 * 48750 = 4875.
So, the price after first discount will be 48750 - 4875 = 43875.

Let’s assume that the second discount of x% reduces the price by x/100 * 43875 = x * 438.75.
So, the final selling price after two discounts is 40365.

We can equate these two values to find the value of x:

43875 - x * 438.75 = 40365
x * 438.75 = 3510
x = 8

Therefore, the value of x is 8%.