the sum of ages of 5 children born at the intervals of 3 years each is 50 years. what is the age of the youngest child?
Answer: Let’s denote the age of the youngest child by x. Then the ages of the other children are x+3, x+6, x+9, and x+12, since they were all born at intervals of 3 years.
The sum of their ages is given as 50 years, so we can write an equation:
x + (x+3) + (x+6) + (x+9) + (x+12) = 50
Simplifying this equation, we get:
5x + 30 = 50
Subtracting 30 from both sides, we get:
5x = 20
Dividing both sides by 5, we get:
x = 4
Therefore, the age of the youngest child is 4 years old.