two students appeared at an examination. one of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. what are the marks obtained by them?
two students appeared at an examination. one of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. what are the marks obtained by them?
Answer: Let’s assume that the first student scored x marks. According to the problem, the second student secured 9 marks more than the first student, which means their score was (x+9).
We are given that the score of the second student was 56% of the sum of the scores of both students. So, we can write an equation as follows:
(x+9) = 0.56(x + (x+9))
Simplifying this equation, we get:
x + 9 = 0.56(2x + 9)
Expanding the brackets, we get:
x + 9 = 1.12x + 5.04
Subtracting x from both sides, we get:
9 = 0.12x + 5.04
Subtracting 5.04 from both sides, we get:
3.96 = 0.12x
Dividing by 0.12, we get:
x = 33
Therefore, the first student scored 33 marks and the second student scored (33+9) = 42 marks.
So, the marks obtained by them are 33 and 42.