What is the mass of sodium acetate required to make 200 ml of 0.245 molar aqueous solution

General
1

what is the mass of sodium acetate required to make 200 ml of 0.245 molar aqueous solution

2

What is the mass of sodium acetate required to make 200 ml of 0.245 molar aqueous solution?

Answer:
To determine the mass of sodium acetate (NaC₂H₃O₂) required to make 200 ml of a 0.245 M aqueous solution, follow these steps:

  1. Calculate the moles of sodium acetate needed:

    • Molarity (M) is defined as the number of moles of solute per liter of solution.
    • Use the formula:
      \text{Moles of solute} = \text{Molarity} \times \text{Volume of solution in liters}
    • Given:
      \text{Molarity} = 0.245 \, \text{M}
      \text{Volume} = 200 \, \text{ml} = 0.200 \, \text{L}
    • Calculate the moles:
      \text{Moles of NaC₂H₃O₂} = 0.245 \, \text{M} \times 0.200 \, \text{L} = 0.049 \, \text{moles}

  2. Calculate the molar mass of sodium acetate:

    • The molar mass of NaC₂H₃O₂ can be calculated by summing the atomic masses of its constituent atoms:
      \text{Na} = 22.99 \, \text{g/mol}
      \text{C} = 12.01 \, \text{g/mol} \times 2 = 24.02 \, \text{g/mol}
      \text{H} = 1.01 \, \text{g/mol} \times 3 = 3.03 \, \text{g/mol}
      \text{O} = 16.00 \, \text{g/mol} \times 2 = 32.00 \, \text{g/mol}
    • Summing these:
      \text{Molar mass of NaC₂H₃O₂} = 22.99 + 24.02 + 3.03 + 32.00 = 82.04 \, \text{g/mol}

  3. Calculate the mass of sodium acetate:

    • Use the formula:
      \text{Mass} = \text{Moles} \times \text{Molar mass}
    • Given:
      \text{Moles of NaC₂H₃O₂} = 0.049 \, \text{moles}
      \text{Molar mass of NaC₂H₃O₂} = 82.04 \, \text{g/mol}
    • Calculate the mass:
      \text{Mass of NaC₂H₃O₂} = 0.049 \, \text{moles} \times 82.04 \, \text{g/mol} = 4.02 \, \text{g}

Therefore, the mass of sodium acetate required to make 200 ml of a 0.245 M aqueous solution is 4.02 grams.