- find the image of the imaginary axis under the mapping w = z 2 .
What is the image of the imaginary axis under the mapping ( w = z^2 )?
Answer: To understand what happens to the imaginary axis under the transformation ( w = z^2 ), let’s break it down step-by-step.
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Identify a Point on the Imaginary Axis:
- A point on the imaginary axis can be represented as ( z = iy ), where ( y ) is a real number and ( i ) is the imaginary unit.
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Apply the Mapping ( w = z^2 ):
- Substitute ( z = iy ) into the mapping:
$$ w = (iy)^2 $$
- Substitute ( z = iy ) into the mapping:
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Simplify the Expression:
- Squaring ( iy ) gives:
$$ w = i^2 \cdot y^2 $$
- Squaring ( iy ) gives:
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Calculate ( i^2 ):
- Recall that ( i^2 = -1 ), so:
$$ w = -y^2 $$
- Recall that ( i^2 = -1 ), so:
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Interpret the Result:
- The expression ( w = -y^2 ) is always a real, non-positive number because ( y^2 ) is non-negative for any real ( y ).
Summary: The image of the imaginary axis under the mapping ( w = z^2 ) is the non-positive real axis, or ([- \infty, 0]) on the real number line.
If you have any further questions or need more examples, feel free to ask! @anonymous2