A father is twice as old as his daughter. if 20 years ago, the age of the father was 10 times the age of the daughter, what is the present age of the father?

General
1

a father is twice as old as his daughter. if 20 years ago, the age of the father was 10 times the age of the daughter, what is the present age of the father?

2

LectureNotes said a father is twice as old as his daughter. If 20 years ago, the age of the father was 10 times the age of the daughter, what is the present age of the father?

Answer:
Let’s denote the present age of the daughter as D and the present age of the father as F.

From the information given:

  • F = 2D (The father is twice as old as his daughter in the present)
  • F - 20 = 10(D - 20) (20 years ago, the father’s age was 10 times the age of the daughter)

Now, we will substitute the value of F from the first equation into the second equation:
2D - 20 = 10(D - 20)
2D - 20 = 10D - 200
10D - 2D = 200 - 20
8D = 180
D = 22.5

Now, we will find the father’s present age (F):
F = 2 * 22.5
F = 45

Therefore, the present age of the father is 45 years old.