A kettle transfers 6,000j of energy electrically. 1,500j of this is wasted. what is the efficiency of this kettle? give your answer as a percentage

General
1

a kettle transfers 6,000j of energy electrically. 1,500j of this is wasted. what is the efficiency of this kettle? give your answer as a percentage.

2

a kettle transfers 6,000j of energy electrically. 1,500j of this is wasted. what is the efficiency of this kettle? give your answer as a percentage.

Answer:
The efficiency of the kettle can be calculated using the formula:

efficiency = (useful energy output / total energy input) x 100%

In this case, the useful energy output is:

useful energy output = total energy input - wasted energy

Substituting the given values, we get:

useful energy output = 6,000 J - 1,500 J = 4,500 J

Now we can calculate the efficiency:

efficiency = (4,500 J / 6,000 J) x 100% = 75%

Therefore, the efficiency of the kettle is 75%.