A rectangle has area 16 m^2 . Express the perimeter of the rectangle as a function of the length of one of its sides.
A rectangle has area 16 m². Express the perimeter of the rectangle as a function of the length of one of its sides.
Answer: To express the perimeter of the rectangle as a function of the length of one of its sides, let’s denote the length of one side as ( l ) (in meters). Given that the area of the rectangle is 16 m², we can find the other side’s length in terms of ( l ).
Step-by-Step Solution:
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Area of the Rectangle:
The area ( A ) of a rectangle is given by the product of its length ( l ) and width ( w ):A = l \times wGiven that the area ( A ) is 16 m²:
l \times w = 16 -
Express Width in Terms of Length:
Solving for ( w ) in terms of ( l ):w = \frac{16}{l} -
Perimeter of the Rectangle:
The perimeter ( P ) of a rectangle is given by the sum of all its sides:P = 2l + 2wSubstitute ( w ) with ( \frac{16}{l} ):
P = 2l + 2\left(\frac{16}{l}\right)Simplify the expression:
P = 2l + \frac{32}{l}
Final Function:
The perimeter ( P ) of the rectangle as a function of the length ( l ) of one of its sides is:
This function ( P(l) ) gives the perimeter of the rectangle for any given length ( l ) of one side, provided ( l ) is a positive real number.