ag2s 0.25 mole mass
What is the molar mass of Ag₂S and how much does 0.25 moles weigh?
Answer: To find the mass of 0.25 moles of silver sulfide (Ag₂S), you first need to calculate its molar mass.
Step 1: Calculate the Molar Mass of Ag₂S
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Silver (Ag): Each atom has a molar mass of approximately 107.87 grams/mole. Since there are two Ag atoms in Ag₂S, you calculate:
$$2 \times 107.87 , \text{g/mol} = 215.74 , \text{g/mol}$$
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Sulfur (S): Has a molar mass of approximately 32.07 grams/mole.
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Total Molar Mass of Ag₂S: Add the mass of the silver and sulfur together:
$$215.74 , \text{g/mol} + 32.07 , \text{g/mol} = 247.81 , \text{g/mol}$$
Step 2: Calculate the Mass of 0.25 Moles of Ag₂S
To find the mass of 0.25 moles of Ag₂S, multiply the molar mass by 0.25:
0.25 \, \text{moles} \times 247.81 \, \text{g/mol} = 61.9525 \, \text{g}
Conclusion
0.25 moles of Ag₂S weigh approximately 61.95 grams.
Summary: By calculating the molar mass of Ag₂S (247.81 g/mol) and multiplying by the number of moles (0.25), we find that 0.25 moles of Ag₂S weigh about 61.95 grams.