Find the angle which is four times its complement

find the angle which is four times its complement

Find the angle which is four times its complement

Concept of Complementary Angles

Complementary angles are a pair of angles whose measures add up to 90^\circ. If two angles are complementary, it implies that the sum of their measures is always three right angles.

For example:

  • If one angle is 30^\circ, its complement is 60^\circ because 30^\circ + 60^\circ = 90^\circ.

Now, we need to find an angle that is four times its complementary angle.

Step-by-Step Solution

  1. Define the Angles:

    Let’s denote the angle we need to find as x^\circ.

  2. Determine the Complementary Angle:

    Since x^\circ and its complement add up to 90^\circ, the complementary angle would be (90^\circ - x^\circ).

  3. Set Up the Equation:

    According to the problem, the angle x^\circ is four times its complement. Therefore, we can set up the following equation:
    $$ x = 4(90 - x) $$

  4. Simplify the Equation:

    Let’s solve for x step-by-step.

    • First, distribute the (4) on the right side:
      $$ x = 360 - 4x $$

    • Next, add (4x) to both sides to bring all terms involving (x) to one side:
      $$ x + 4x = 360 $$

    • Combine like terms:
      $$ 5x = 360 $$

  5. Solve for (x):

    Divide both sides by (5):
    $$ x = \frac{360}{5} $$
    $$ x = 72 $$

    Therefore, the angle we need to find is 72^\circ.

  6. Verify the Solution:

    To ensure our solution is correct, let’s verify it:

    • The complement of (72^\circ) is (90^\circ - 72^\circ = 18^\circ).
    • Check if (72^\circ) is indeed four times its complement:
      • (4 \times 18^\circ = 72^\circ).

    The conditions of the problem are satisfied, confirming our solution is accurate.

Summary

In conclusion, the angle that is four times its complement is 72^\circ, and its complement is 18^\circ. Solving such problems involves using basic algebraic methods, applying the concept of complementary angles, and ensuring the solution satisfies the given condition. @anonymous6