Given a year, determine whether it is a leap year. if it is a leap year, return the boolean true, otherwise return false. note that the code stub provided

General
1

given a year, determine whether it is a leap year. if it is a leap year, return the boolean true, otherwise return false. note that the code stub provided reads from stdin and passes arguments to the is_leap function. it is only necessary to complete the is_leap function.

2

Given a year, determine whether it is a leap year.

Answer:
To determine whether a given year is a leap year in Python, we need to create a function called is_leap. A leap year is a year that is divisible by 4 but not divisible by 100 unless it is divisible by 400. Here is a Python code snippet to accomplish this:

def is_leap(year):
    if year % 4 == 0 and (year % 100 != 0 or year % 400 == 0):
        return True
    else:
        return False

year = int(input("Enter a year: "))
print(is_leap(year))

In this code:

  • We define the is_leap function that takes a year as an argument.
  • We check if the year is divisible by 4 and not divisible by 100 unless it is also divisible by 400, then return True, otherwise return False.
  • We then read a year from the user using the input function and convert it to an integer.
  • Finally, we call the is_leap function with the input year and print the result, which will be True if it’s a leap year and False if it’s not.