how much copper is obtained from 100g of cuso4
How much copper is obtained from 100g of CuSO4?
Answer: To determine how much copper is obtained from 100g of CuSO₄ (Copper(II) sulfate), we need to use the concept of molar mass and stoichiometry.
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Calculate the Molar Mass of CuSO₄:
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Copper (Cu): 1 atom × 63.55 g/mol = 63.55 g/mol
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Sulfur (S): 1 atom × 32.07 g/mol = 32.07 g/mol
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Oxygen (O): 4 atoms × 16.00 g/mol = 64.00 g/mol
So, the molar mass of CuSO₄ is:
63.55 \, \text{g/mol} \, (Cu) + 32.07 \, \text{g/mol} \, (S) + 4 \times 16.00 \, \text{g/mol} \, (O) = 159.62 \, \text{g/mol}
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Determine the Fraction of Copper in CuSO₄:
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Since the molar mass of Cu is 63.55 g/mol and the molar mass of CuSO₄ is 159.62 g/mol, the fraction of Cu in CuSO₄ is:
\text{Fraction of Cu} = \frac{63.55 \, \text{g/mol}}{159.62 \, \text{g/mol}}Simplifying this,
\text{Fraction of Cu} = \frac{63.55}{159.62} \approx 0.398
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Calculate the Mass of Copper in 100g of CuSO₄:
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Using the fraction of copper, we can find the mass of copper in 100g of CuSO₄:
\text{Mass of Cu} = 100 \, \text{g} \times 0.398 = 39.8 \, \text{g}
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Final Answer: From 100g of CuSO₄, you can obtain approximately 39.8 grams of copper.