in the circuit source voltage is 5v and capacitor is 4v find voltage across resistor
In the circuit source voltage is 5V and capacitor is 4V. Find voltage across resistor.
Answer:
To find the voltage across the resistor in this circuit, we’ll use Kirchhoff’s Voltage Law, which states that the sum of all the voltages around a closed loop in a circuit is equal to zero.
Let’s break it down step by step:
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Identify Voltages in the Circuit:
- The source voltage (V_{\text{source}}) is given as 5V.
- The voltage across the capacitor (V_{\text{capacitor}}) is 4V.
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Apply Kirchhoff’s Voltage Law:
- The law states:V_{\text{source}} = V_{\text{capacitor}} + V_{\text{resistor}}
- We need to find V_{\text{resistor}}, the voltage across the resistor.
- The law states:
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Solve for the Voltage Across the Resistor:
- Rearranging the equation gives:V_{\text{resistor}} = V_{\text{source}} - V_{\text{capacitor}}
- Substituting the known values:V_{\text{resistor}} = 5\,\text{V} - 4\,\text{V} = 1\,\text{V}
- Rearranging the equation gives:
Summary: The voltage across the resistor is 1V. This is calculated using Kirchhoff’s Voltage Law by subtracting the voltage across the capacitor from the source voltage.