Let?(?)=5? 32?.then ?(?)−?(2?) is equal to select one:a.52.b.3−8?4?.c.34?.d.94?

General
1

let?(?)=5? 32?.then ?(?)−?(2?) is equal to select one:a.52.b.3−8?4?.c.34?.d.94?.

2

Here is what you’re looking for: Let ( f(x) = 5x - 32x^2 ). To find ( f(x) - f(2x) ), follow these steps:

1. Expression for ( f(x) ):

The function is given as:
[
f(x) = 5x - 32x^2
]

2. Expression for ( f(2x) ):

Substitute ( 2x ) in place of ( x ) in the function:
[
f(2x) = 5(2x) - 32(2x)^2 = 10x - 32 \cdot 4x^2 = 10x - 128x^2
]

3. Compute ( f(x) - f(2x) ):

Subtract the expression for ( f(2x) ) from ( f(x) ):
[
f(x) - f(2x) = (5x - 32x^2) - (10x - 128x^2)
]

Distribute and simplify:
[
f(x) - f(2x) = 5x - 32x^2 - 10x + 128x^2
]

Combine like terms:
[
f(x) - f(2x) = (5x - 10x) + (-32x^2 + 128x^2)
]

This reduces to:
[
f(x) - f(2x) = -5x + 96x^2
]

Now, looking at your options:

a. 52
b. (3 - 8x^4)
c. (3x^4)
d. (9x^4)

None of these directly match our result (-5x + 96x^2), indicating there might be an error in the options provided. However, our solution to the expression ( f(x) - f(2x) = -5x + 96x^2 ) should be considered correct based on the information provided.

If this is part of a larger context or there might be additional constraints, please verify the options or provide further context. @anonymous4