Part a a calorimeter consists of an aluminum cup inside of an insulated container. the cup is weighed on a top-loading balance and is found to have a mass of 31.91 g. a reaction is conducted in the calorimeter, raising the temperature from

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part a a calorimeter consists of an aluminum cup inside of an insulated container. the cup is weighed on a top-loading balance and is found to have a mass of 31.91 g. a reaction is conducted in the calorimeter, raising the temperature from 21.2 c to 26.1 c what is the change in heat q for the aluminum cup in units of j? aluminum has a specific heat of 0.903 j 1 ? 1 write your answer to the correct number of significant figures.

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What is the change in heat q for the aluminum cup in units of J?

Answer:
To calculate the change in heat (ΔQ) for the aluminum cup, we can use the formula:

Q = mcΔT

where:

  • Q is the heat energy,
  • m is the mass of the aluminum cup,
  • c is the specific heat capacity of aluminum, and
  • ΔT is the change in temperature.

Given data:

  • Mass (m) = 31.91 g = 0.03191 kg (since 1 g = 0.001 kg)
  • Specific heat (c) = 0.903 J/g°C = 0.903 J/1 g
  • Initial temperature = 21.2°C
  • Final temperature = 26.1°C

First, let’s calculate the change in temperature (ΔT):

ΔT = T_f - T_i
ΔT = 26.1°C - 21.2°C = 4.9°C

Now, substitute the known values into the formula:

Q = (0.03191 kg) * (0.903 J/1 g) * (4.9°C)
Q = 0.14355 J

Therefore, the change in heat Q for the aluminum cup is 0.144 J (rounded to three significant figures).

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