The difference between integers is 5. their product is 500. find the numbers

the difference between integers is 5. their product is 500. find the numbers.

What are two numbers whose difference is 5 and whose product is 500?

Answer:

To solve this problem, we need to set up an equation based on the conditions given: the difference between the two integers is 5, and their product is 500.

Step 1: Setting Up the Equations

  1. Define the Variables:

    • Let the two integers be x and y.
    • Given that x - y = 5.
    • Given that x \cdot y = 500.
  2. Rewrite x in Terms of y:

    • From the equation x - y = 5, we can express x as:
      $$x = y + 5$$

Step 2: Substituting and Solving

  1. Substitute x in the Product Equation:

    • Substitute x = y + 5 into the equation x \cdot y = 500:
      $$(y + 5) \cdot y = 500$$
  2. Expand and Simplify:

    • Expand the equation:
      $$y^2 + 5y = 500$$
  3. Rearrange into Standard Quadratic Form:

    • Rearrange the terms to get a standard quadratic equation:
      $$y^2 + 5y - 500 = 0$$

Step 3: Solving the Quadratic Equation

  1. Use the Quadratic Formula:

    • The quadratic formula for ax^2 + bx + c = 0 is:
      y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
    • Here, a = 1, b = 5, c = -500.
  2. Calculate the Discriminant:

    • Calculate the discriminant (b^2 - 4ac):
      $$5^2 - 4 \cdot 1 \cdot (-500) = 25 + 2000 = 2025$$
  3. Find y Using the Quadratic Formula:

    • Substitute the values into the quadratic formula:
      y = \frac{-5 \pm \sqrt{2025}}{2}
    • Evaluate the square root and solve:
      • \sqrt{2025} = 45
  4. Calculate the Two Possible Values for y:

    • y = \frac{-5 + 45}{2} = 20
    • y = \frac{-5 - 45}{2} = -25

Step 4: Determine Corresponding Values for x

  1. For y = 20:

    • Substitute back to find x:
      $$x = y + 5 = 20 + 5 = 25$$
  2. For y = -25:

    • Substitute back to find x:
      $$x = y + 5 = -25 + 5 = -20$$

Final Answer:

The two pairs of integers that satisfy the given conditions are:

  • (20, 25)
  • (-25, -20)

Both pairs meet the criteria of having a difference of 5 and a product of 500.