The dissociation equilibrium of a gas ab2

General
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the dissociation equilibrium of a gas ab2

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What is the dissociation equilibrium of a gas AB₂?

Answer: The dissociation equilibrium of a gas like AB₂ refers to the balance between the forward and reverse reactions when it partially breaks down into its components. For the gas AB₂, it dissociates into A and B molecules:

\text{AB}_2 \rightleftharpoons \text{A} + 2\text{B}

This process reaches equilibrium when the rate at which AB₂ dissociates into A and B is equal to the rate at which A and B recombine to form AB₂. The equilibrium can be described by the equilibrium constant K_c, which is defined for this reaction in terms of the concentrations of the products and reactants:

K_c = \frac{[\text{A}][\text{B}]^2}{[\text{AB}_2]}

Where:

  • [\text{A}] is the concentration of A.
  • [\text{B}] is the concentration of B.
  • [\text{AB}_2] is the concentration of AB₂.

Factors Affecting Equilibrium:

  1. Concentration: Changing the concentration of any of the reactants or products will shift the equilibrium to restore balance, according to Le Chatelier’s Principle.

  2. Pressure: For gas-phase reactions, changes in pressure can affect equilibrium. Increasing pressure tends to shift the equilibrium towards the side with fewer gas molecules.

  3. Temperature: An increase in temperature will favor the endothermic direction (absorbing heat), while a decrease favors the exothermic direction (releasing heat).

  4. Catalysts: These speed up both the forward and reverse reactions equally, allowing equilibrium to be reached faster, but do not change the position of equilibrium.

Summary: The dissociation equilibrium of a gas AB₂ involves the balance between its dissociation into A and B and their recombination. This balance depends on concentration, pressure, temperature, and catalysts. Understanding these factors helps in controlling and predicting the behavior of the reaction.