the exponent of 7 in prime factorization of 4018 is
The exponent of 7 in prime factorization of 4018 is
Answer:
To find the exponent of 7 in the prime factorization of 4018, we need to factorize 4018 into its prime factors.
First, let’s divide 4018 by 7:
\frac{4018}{7} = 574
Now, continue to factorize 574:
\frac{574}{2} = 287
Further factorizing 287:
\frac{287}{7} = 41
Since 41 is a prime number, we have found all the prime factors of 4018:
4018 = 2 \times 7^2 \times 41
Therefore, the exponent of 7 in the prime factorization of 4018 is 2.