The number of tokens in the following C statement is printf ("i = %d, &i = %x", i, &i);

General
1

The number of tokens in the following C statement is

printf (“i = %d, &i = %x”, i, &i);

2

The number of tokens in the following C statement is printf(“i = %d, &i = %x”, i, &i);

Answer:
In the given C statement, the number of tokens can be identified by breaking down each distinct element of the code. Tokens in C language generally include keywords, identifiers, constants, string literals, operators, and other separators.

The given statement is:

printf("i = %d, &i = %x", i, &i);

Let’s identify the tokens step-by-step:

  1. printf: This is a function call, and it is considered a single token.
  2. (: The opening parenthesis is a token that denotes the beginning of the argument list for the function.
  3. “i = %d, &i = %x”: This is a string literal, and it is treated as one token.
  4. ,: This comma is a token that separates arguments in the function call.
  5. i: This is an identifier token representing a variable.
  6. ,: Another comma token separating arguments.
  7. &i: This consists of two tokens:
    • &: This is the address-of operator.
    • i: This is another identifier token representing a variable.
  8. ): The closing parenthesis is a token that denotes the end of the argument list for the function.
  9. ;: The semicolon is a token that marks the end of the statement.

Now, let’s count each token:

  1. printf
  2. (
  3. "i = %d, &i = %x"
  4. ,
  5. i
  6. ,
  7. &
  8. i
  9. )
  10. ;

Final Answer:
The number of tokens in the given C statement printf("i = %d, &i = %x", i, &i); is 10.