The number of tokens in the following C statement is printf(“i = %d, &i = %x”, i, &i);
Answer:
In the given C statement, the number of tokens can be identified by breaking down each distinct element of the code. Tokens in C language generally include keywords, identifiers, constants, string literals, operators, and other separators.
The given statement is:
printf("i = %d, &i = %x", i, &i);
Let’s identify the tokens step-by-step:
printf: This is a function call, and it is considered a single token.
(: The opening parenthesis is a token that denotes the beginning of the argument list for the function.
“i = %d, &i = %x”: This is a string literal, and it is treated as one token.
,: This comma is a token that separates arguments in the function call.
i: This is an identifier token representing a variable.
,: Another comma token separating arguments.
&i: This consists of two tokens:
&: This is the address-of operator.
i: This is another identifier token representing a variable.
): The closing parenthesis is a token that denotes the end of the argument list for the function.
;: The semicolon is a token that marks the end of the statement.
Now, let’s count each token:
printf
(
"i = %d, &i = %x"
,
i
,
&
i
)
;
Final Answer:
The number of tokens in the given C statement printf("i = %d, &i = %x", i, &i); is 10.