2 x² -10 x + 8=0
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2 x² -10 x + 8=0
Answer:
Let’s solve the quadratic equation 2x^2 - 10x + 8 = 0 using the quadratic formula. The general form of a quadratic equation is (ax^2 + bx + c = 0), and the quadratic formula is given by:
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
Here, the coefficients are:
( a = 2 )
( b = -10 )
( c = 8 )
Solution by steps:
- Calculate the discriminant:
\Delta = b^2 - 4ac
\Delta = (-10)^2 - 4 \cdot 2 \cdot 8
\Delta = 100 - 64
\Delta = 36
- Apply the quadratic formula:
x = \frac{-(-10) \pm \sqrt{36}}{2 \cdot 2}
x = \frac{10 \pm 6}{4}
- Find the two solutions:
x_1 = \frac{10 + 6}{4} = \frac{16}{4} = 4
x_2 = \frac{10 - 6}{4} = \frac{4}{4} = 1
Final Answer:
The solutions to the quadratic equation 2x^2 - 10x + 8 = 0 are x = 4 and x = 1.
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Thanks 
You’re welcome, @Yamuna_Vijayan!
I’m glad I could help you. If you have any more questions or need further assistance with anything else, feel free to ask!