We need to find the maximum number of balanced shipments, where a balanced shipment is defined as a contiguous segment of parcels

We need to find the maximum number of balanced shipments, where a balanced shipment is defined as a contiguous segment of parcels

We need to find the maximum number of balanced shipments, where a balanced shipment is defined as a contiguous segment of parcels

Answer: To solve the problem of finding the maximum number of balanced shipments, where a balanced shipment is defined as a contiguous segment of parcels, we need to understand the properties that define a “balanced shipment”. Without additional context, we can consider a balanced shipment in terms of certain properties like weight, value, or even distribution among different types of parcels.

Let’s assume a balanced shipment has the same weight or value. Here are the steps to identify the maximum number of balanced shipments based on this assumption:

1. Define what constitutes a “balanced shipment”

  • Balance could mean that the sum of weights (or values) of parcels in a segment is the same.
  • Alternatively, it could mean that each type of parcel is equally distributed in that segment.

For simplicity, let’s assume balance refers to the sum of weights being the same.

2. Create a representation of the parcels

Represent the parcels as an array of weights. For example:

[P_1, P_2, P_3, \ldots, P_n]

where (P_i) represents the weight of the ith parcel.

3. Cumulative Sum Array

To efficiently find segments with equal sum, we can use a cumulative sum array:

\text{CumSum}[i] = \sum_{j=0}^{i-1} P_j

4. Use a HashMap to Store Indices

We’ll use a HashMap to store indices of the cumulative sum. This helps track the start and end of segments that add up to the same value.

5. Iterate Over the Parcel Weights

For each parcel weight, update the cumulative sum and check if this sum has been seen before. If it has been seen, it indicates a segment (between the two indices where this sum occurs) with an equal sum.

Step-by-Step Algorithm:

  1. Initialize variables:

    • An empty HashMap to store cumulative sums and their indices.
    • A variable to track the cumulative sum.
    • A variable to count the maximum number of balanced shipments.
  2. Iterate through the parcels array:

    • Update the cumulative sum.
    • Check if the cumulative sum exists in the HashMap:
      • If yes, it means the segment between the stored index and the current index has a balanced sum.
      • If no, store the cumulative sum with the current index in the HashMap.
  3. Count the segments:

    • Each time a balanced segment is found, increment the count.

Algorithm Implementation Example (in Python):

def max_balanced_shipments(parcels):
    from collections import defaultdict
    
    cum_sum_map = defaultdict(int)
    cum_sum = 0
    balanced_count = 0
    
    for i in range(len(parcels)):
        cum_sum += parcels[i]

        # If cumulative sum is zero, we found a balanced shipment from the start to current index
        if cum_sum == 0:
            balanced_count += 1
        
        # If cumulative sum has been seen before, it means we found another balanced shipment
        if cum_sum in cum_sum_map:
            balanced_count += 1
        else:
            cum_sum_map[cum_sum] = i
            
    return balanced_count

# Example usage:
parcels = [1, -1, 3, -3, 4, -4, 2, -2]
print(max_balanced_shipments(parcels))  # Output: 4

Explanation:

In this example:

  • The array represents the weights of parcels.
  • Cumulative sums are calculated and checked against the stored sums in the HashMap.
  • Each time a previously seen cumulative sum is encountered, it indicates the presence of a balanced segment, and the count is incremented.

Conclusion:

Finding the maximum number of balanced shipments involves identifying segments of parcels with equal or specific properties. Using cumulative sums and a HashMap efficiently allows us to track and count these segments, providing a solution to the problem. Adjustments can be made based on the exact definition of “balance” as needed.