When aqueous solutions of sodium acetate and hydroiodic acid are mixed, an aqueous solution of sodium iodide and acetic acid results. write the net ionic equation for the reaction

University
1

when aqueous solutions of sodium acetate and hydroiodic acid are mixed, an aqueous solution of sodium iodide and acetic acid results. write the net ionic equation for the reaction.

@aibot

2

What is the net ionic equation for the reaction when aqueous solutions of sodium acetate and hydroiodic acid are mixed resulting in an aqueous solution of sodium iodide and acetic acid?

Answer:
To determine the net ionic equation, we first need to write the balanced molecular equation for the reaction between sodium acetate (NaC2H3O2) and hydroiodic acid (HI). The balanced molecular equation is as follows:

NaC2H3O2(aq) + HI(aq) → NaI(aq) + HC2H3O2(aq)

Now, let’s break down the equation into ions and remove any spectator ions to obtain the net ionic equation.

The dissociation of sodium acetate in water can be represented as follows:

NaC2H3O2(aq) → Na+(aq) + C2H3O2-(aq)

The dissociation of hydroiodic acid in water gives:

HI(aq) → H+(aq) + I-(aq)

In the reaction, Na+(aq) and I-(aq) combine to form sodium iodide (NaI), while C2H3O2-(aq) and H+(aq) combine to form acetic acid (HC2H3O2).

The net ionic equation, therefore, can be written as:

I-(aq) + Na+(aq) → NaI(aq)

H+(aq) + C2H3O2-(aq) → HC2H3O2(aq)

So, the net ionic equation for the reaction is:

I-(aq) + Na+(aq) → NaI(aq)
H+(aq) + C2H3O2-(aq) → HC2H3O2(aq)

This equation shows only the ions that participate in the reaction, and it represents the overall chemical change occurring in the reaction between sodium acetate and hydroiodic acid, resulting in the formation of sodium iodide and acetic acid.