Which data type is most suitable for storing a number 65000 in a 32-bit system?

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which data type is most suitable for storing a number 65000 in a 32-bit system?

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Which data type is most suitable for storing a number 65000 in a 32-bit system?

Answer: When deciding the most suitable data type for storing a number like 65000 in a 32-bit system, it is essential to understand the characteristics and capacity of various data types.

Common Data Types in a 32-bit System:

  1. int (Integer):

    • Storage Size: 32 bits (4 bytes)
    • Range: Typically from -2,147,483,648 to 2,147,483,647
    • Signed/Unsigned Variants: Can store both positive and negative numbers if signed; only positive numbers if unsigned.

  2. short (Short Integer):

    • Storage Size: 16 bits (2 bytes)
    • Range: From -32,768 to 32,767 (signed short); 0 to 65,535 (unsigned short)

  3. long (Long Integer):

    • Storage Size: 32 bits (4 bytes)
    • Range: Similar to int in a 32-bit system, from -2,147,483,648 to 2,147,483,647

  4. char (Character):

    • Storage Size: 8 bits (1 byte)
    • Range: -128 to 127 (signed); 0 to 255 (unsigned)
    • Note: Primarily used to store characters.

Best Suitable Data Type for Storing 65000:

  • The number 65,000 is within the unsigned short range (0 to 65,535).
  • Although you can use larger data types like int or long, using unsigned short is more efficient in terms of memory usage because it only requires 16 bits rather than 32 bits.

Conclusion:

Therefore, the most suitable data type for storing the number 65000 in a 32-bit system is unsigned short.

// Example in C
unsigned short number = 65000;

Using an unsigned short ensures that you are using memory resources efficiently while still being capable of storing the number 65000.

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