calculate the electrochemical equivalent of silver in silver nitrate.
The electrochemical equivalent of silver 0.0011180 g. When an electric current of0.5 ampere is passed through an aqueous silver nitrate solution for 200 sec., the amount of silver deposited is
(1) 1.1180 g(3) 5.590g) 0.11180 g(4) 0.5590 g
The electrochemical equivalent of silver 0.0011180 g. When an electric current of0.5 ampere is passed through an aqueous silver nitrate solution for 200 sec., the amount of silver deposited is(1) 1.1180 g(3) 5.590g) 0.11180 g(4) 0.5590 g
Answer:
the amount of substance= 0.001118 g deposited,
Amount of charge passed= Ixt,
=0.5x200
=200 coulomb
Amount of Ag deposited: 100x0.001118=0.01118 g